The hybridisation in $P {C l}_{5}$ molecule is:

{s p}^{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{s p}^{3} d^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{s p}^{3} d

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

{s p}^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C ${s p}^{3} d$
Phosphorus has 5 valence electrons. 1 electron each is shared by chlorine atom hence, $P C l_{5}$ molecule has $s p^{3} d$ hybridisation and hence trigonal bipyramidal shape.

Suggest Corrections

Similar questions

The correct order of hybridisation of the central atom in the following species $N H_{3}$ , ${[P t C l_{4}]}^{2 -}$ , $P C l_{5}$ and $B C l_{3}$

In the molecule CH ≡ C -CH = $C H_{2}$ , the hybridisation of C -Cbond is

s p^{3}, s p^{2}, s p^{2}, s p^{3}

The correct order of hybridization of the central atom in the following species $N H_{3}, [P t C l_{4}]^{2 -}$ , $P C l_{5}$ and $B C l_{3}$ is

C (1) H_{2} = C (2) H - C (3) \equiv C H