Question

The hybridization of $PC{l}_5$ molecule in its ionic state is:

• A. $s{p}^{3}d$
• B. $s{p}^3$
• C. $s{p}^3{d}^2$
• D. Both b and c

Answer 1

The correct option is D Both b and c

$PC{l}_5$ is expected to have a hybridisation of $s{p}^{3}d$ and a shape of trigonal bipyramidal. But in solid state $PC{l}_5$ exists in ionic form as $PC{l}_4^{+}$ and $PC{l}_6^{-}$ and thus shows $s{p}^3$ and $s{p}^3{d}^2$ hybridisations, respectively.