the image of the plane x+y+z+1=0 through the plane 2x+3y-5z+6=0 i

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x + y + z + 1 = 0

2 x - 3 y + 5 z - 2 = 0

(- 1, 2, 1)

The equation of plane through the intersection of planes (x+y+z =1) and (2x +3y - z+4) =0 is

2 x - y + z = 3

4 x - 3 y + 5 z + 9 = 0

\frac{x + 1}{2} = - \frac{y + 3}{4} = \frac{z - 3}{5}

x + y + z - 6 = 0

2 x + 3 y + 4 z - 5 = 0

(1, 1, 1)

x + y + z - 3 = 0 = 2 x - y + 5 z - 6

x - y - z + 1 = 0 = 2 x + 3 y + 7 z - k

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