Question

# The increase in the length of a wire on stretching is $$0.025 \%$$. If its Poisson's ratio is $$0.4$$, then the percentage decrease in the diameter is :

A
0.01
B
0.02
C
0.03
D
0.04

Solution

## The correct option is A $$0.01$$Suppose, D be the diameter of the wire Poissons ratio,  $$σ=\frac { lateral strain }{ longitudinal strain }$$ $$σ=\frac { \frac { ΔD }{ D } }{ \frac { ΔL }{ L } }$$ $$\frac { ΔL }{ L } =0.025$$ $$σ=0.004$$ $$σ=\frac { \frac { ΔD }{ D } }{ \frac { 1 }{ 40 } }$$ $$\frac { ΔD }{ D } =\frac { 1 }{ 40 } \times 0.4=0.01$$Physics

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