The increasing order of acid strength $H C l O_{4}, H C l O_{3}, H C l O_{2}, H C l O$ is:

H C l O < H C l O_{2} < H C l O_{3} < H C l O_{4}

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H C l O_{4} < H C l O_{3} < H C l O_{2} < H C l O

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H C l O_{4} < H C l O_{2} < H C l O < H C l O_{3}

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none of the above

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Solution

The correct option is A $H C l O < H C l O_{2} < H C l O_{3} < H C l O_{4}$
Higher is the oxidation number of non-metal in oxo-acid, more its acidic nature.

$H C l O < H C l O_{2} < H C l O_{3} < H C l O_{4}$
+1 +3 +5 +7 (highest oxidation no.)

Hence, the correct option is $A$

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Similar questions

Arrange the following compounds according to the increasing order of oxidation state of chlorine.

$H C l O_{4}, H C l O_{3}, H C l O_{2}, H C l O$

H C l O < H C l O_{2} < H C l O_{3} < H C l O_{4}

H C l O < H C l O_{2} < H C l O_{3} < H C l O_{4}

H C l O, H C l O_{2}, H C l O_{3}, H C l O_{4}

H C l O_{4} < H C l O_{3} < H C l O_{2} < H C l O

C l - O

H C l O

H C l O_{2}

H C l O_{3}

H C l O_{4}

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