The increasing order of acidic nature of the following oxides is :

S i O_{2} < P_{2} O_{5} < C l_{2} O_{7} < S O_{3}

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S i O_{2} < P_{2} O_{5} < S O_{3} < C l_{2} O_{7}

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C l_{2} O_{7} < S O_{3} < P_{2} O_{5} < S i O_{2}

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S O_{3} < C l_{2} O_{7} < S i O_{2} < P_{2} O_{5}

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Solution

The correct option is C $S i O_{2} < P_{2} O_{5} < S O_{3} < C l_{2} O_{7}$
In the periodic table, as we move from left to right, the acidic nature of oxides increases.

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Similar questions

Among $A l_{2} O_{3}, S i O_{2}, P_{2} O_{3}, a n d S O_{3}$ , the correct order of acid strength is:

N a_{2} O, M g O, S O_{3}, C l_{2} O_{7}

$H C l O_{4} + P_{2} O_{5} \to$ (A) and (B) A and B are

C a O, S O_{2}, S O_{3}, F e_{2} O_{3}, C l_{2} O_{7}, C O_{2}, N_{2} O

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