Question

The increasing order of basic nature for $N{a}_{2}O,MgO$ and $A{l}_2{O}_3$ is :

• A. $A{l}_2{O}_3$ < $MgO$ < $N{a}_{2}O$
• B. $MgO$ < $N{a}_{2}O$ < $A{l}_2{O}_3$
• C. $A{l}_2{O}_3$ < $N{a}_{2}O$ < $MgO$
• D. $N{a}_{2}O$ < $A{l}_2{O}_3$ < $MgO$

Answer 1

The correct option is A $A{l}_2{O}_3$ < $MgO$ < $N{a}_{2}O$

$N{a}_{2}O$ is the most basic and $A{l}_2{O}_3$ is the least basic. On moving from left to right in a period, the basic character decreases.

Thus, the increasing order of basic character is $A{l}_2{O}_3<MgO<N{a}_{2}O$.