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Question

The increasing order of bond angles in H2S, NH3,BF3 and SiH4 is:

A
H2S<NH3<SiH4<BF3
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B
NH3<H2S<SiH4<BF3
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C
H2S<SiH4<NH3<BF3
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D
H2S<NH3<BF3<SiH4
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Solution

The correct option is A H2S<NH3<SiH4<BF3
The repulsion order is: lone pairlone pair>bond pairlone pair>bond pairbond pair


H2S - has 2 lone pair of electrons and has a bent shape.



NH3 - sp3 hybridised, pyramidal shape


SiH4 - sp3 hybridised, tetrahedral shape


BF3 - sp2 hybridised, trigonal planar shape

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