Question

The increasing order of the rate of reaction with $HN{O}_3/H_{2}S{O}_4$:

• A. $iii<ii<i$
• B. $ii<iii<i$
• C. $i<iii<ii$
• D. $i<ii<iii$

Answer 1

The correct option is D $i<ii<iii$

Reaction with $HN{O}_3|H_{2}S{O}_4$ is an electrophilic substitution and the order of reactivity towards to ESR is:
Now,
(i) Here, both groups attached to benzene are deactivating groups.
(ii)Here, one group which is attached with benzene through 'O' is activating group and other which is attached through $-CO$ is deactivating group.
(iii)Here both the groups attached to benzene ring are activating groups.
Hence,
The increasing order of the rate of reaction is (i) < (ii) < (iii)