The initial velocity of a particle is 10 m/sec and its retardation is 2 m/ $s e c^{2}$ . The distance moved by the particle in $5^{t h}$ second of its motion is

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Solution

The correct option is A

Using the formula for the distance travelled in the $n^{t h}$ second

$S_{n} = u - \frac{a}{2} (2 n - 1) = 10 - \frac{2}{2} (2 \times 5 - 1) = 1$ meter

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The initial velocity of a particle is 10 m/sec and its retardation is 2 m/ $s e c^{2}$ . The distance moved by the particle in $5^{t h}$ second of its motion is

The correct option is A

Using the formula for the distance travelled in the $n^{t h}$ second

$S_{n} = u - \frac{a}{2} (2 n - 1) = 10 - \frac{2}{2} (2 \times 5 - 1) = 1$ meter