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Question

The inner diameter of a cylindrical wooden pipe is 24 cm and its outer diameter is 28 cm.The length of the pipe is 35 cm. Find the mass of the pipe, if 1cm3 of wood has a mass of 0.6 g. [Assume π=227]


A

9.432 kg

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B

4.432 kg

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C

7.432 kg

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D

3.432 kg

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Solution

The correct option is D

3.432 kg


Inner radius (r1) of the cylindrical pipe =(242)cm=12 cm

Outer radius (r2) of the cylindrical pipe =(282)cm=14 cm

Height (h) of the pipe = length of the pipe = 35 cm

Volume of the pipe = π(r22r21)h cm3=110×52 cm3=5720 cm3

Mass of 1 cm3 wood=0.6 g

Mass of 5720 cm3 wood=(5720×0.6) g=3432 g

= 3.432 kg


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