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Question

The integral 1+2cotx(cosec x+cotx)dx (0<x<π2) is equal to. (where C is a constant of integration).

A
2log(cosx2)+C
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B
4log(sinx2)+C
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C
4log(cosx2)+C
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D
2log(sinx2)+C
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Solution

The correct option is D 2log(sinx2)+C
(2cotx cosec x+cosec2x+cot2x)dx

|cosec x+cotx|dx

(cosec x+cotx)dx

1+cosxsinxdx

cotx2dx

2log(sinx2)+c

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