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Question

The integrating factor of the differential equation dydx−ytanx=cosx is:

A
secx
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B
cosx
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C
etanx
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D
cotx
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Solution

The correct option is A cosx
We have,
dydxytanx=cosx

We know that the general equation
dydx+Py=Q

So,
P=tanx,Q=cosx

We know that
I.F=eP dx

Therefore,
I.F=etanx dx

I.F=eln|cosx|

I.F=eln1secx

I.F=1secx

I.F=cosx

Hence, this is the answer.

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