Question

The intensity of magnetic induction field at the centre of a single turn circular coil of radius $5$cm carrying of $0.9$A current is:

• A. $36\pi \times {10}^{-7}$T
• B. $9\pi \times {10}^{-7}T$
• C. $36\pi \times {10}^{-6}T$
• D. $9\pi \times {10}^{-6}T$

Answer 1

The correct option is A $36\pi \times {10}^{-7}$T

Magnetic field at the center of a circular current carrying coil is,

$\frac{{\mu }_{0}i}{2R}=\frac{4\pi \times {10}^{-7}\times 0.9}{2\times 0.05}T$

$=36\pi \times {10}^{-7}T$

Hence correct answer is option A.