The inverse of - 1 a b- 0 x 0- 0 0 1 - is - 1 -a -b- 0 1 0- 0 0 1 - then x-

The correct option is A 1 [ [ [ 1 amp; a amp; b; 0 amp; x amp; 0; 0 amp; 0 amp; 1 ]] [ [ 1 amp; a amp; b; 0 amp; 1 ...

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Finding Inverse Using Elementary Transformations

The inverse o...

Question

The inverse of $⎡ ⎢ ⎣ \begin{matrix} 1 & a & b 0 & x & 0 0 & 0 & 1 \end{matrix} ⎤ ⎥ ⎦$ is $⎡ ⎢ ⎣ \begin{matrix} 1 & - a & - b 0 & 1 & 0 0 & 0 & 1 \end{matrix} ⎤ ⎥ ⎦$ then $x =$

a

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b

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0

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1

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Similar questions

⎧ ⎪ ⎨ ⎪ ⎩ \begin{matrix} 1 & a & b 0 & x & 0 0 & 0 & 1 \end{matrix} ⎫ ⎪ ⎬ ⎪ ⎭

⎧ ⎪ ⎨ ⎪ ⎩ \begin{matrix} 1 & - a & - b 0 & 1 & 0 0 & 0 & 1 \end{matrix} ⎫ ⎪ ⎬ ⎪ ⎭

x =

A = ⎡ ⎢ ⎣ \begin{matrix} 1 & 2 & x 0 & 1 & 0 0 & 0 & 1 \end{matrix} ⎤ ⎥ ⎦

B = ⎡ ⎢ ⎣ \begin{matrix} 1 & - 2 & y 0 & 1 & 0 0 & 0 & 1 \end{matrix} ⎤ ⎥ ⎦

A B = I_{3}

x + y

a b > - 1, b c > - 1

c a > - 1

{cot}^{- 1} (\frac{a b + 1}{a - b}) + {cot}^{- 1} (\frac{b c + 1}{b - c}) + {cot}^{- 1} (\frac{c a + 1}{c - a})

a, b

c

a^{- 1}, b^{- 1}, c^{- 1}

[a, b, c] \neq 0

[a^{- 1}, b^{- 1}, c^{- 1}]

A = ⎡ ⎢ ⎣ \begin{matrix} 1 & 0 & 0 a & 1 & 0 b & c & 1 \end{matrix} ⎤ ⎥ ⎦

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