CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

The ionisation potential of hydrogen atom is 13.6 eV. The hydrogen atom in the ground state is excited by the monochromatic light of energy 12.1 eV. 

The spectral lines emitted by hydrogen according to Bohr's theory will be: 


A
one
loader
B
two
loader
C
three
loader
D
four
loader

Solution

The correct option is D three
Since ionisation potential of hydrogen atom is 13.6 eV.
$$\therefore E_1=-13.6 eV$$
Now, $$ E_n-E_1=\dfrac{-13.6}{n^2}-(-13.6)=12.1$$
$$\dfrac{-13.6}{n^2}+13.6=12.1$$
$$\therefore n=3$$
After absorbing 12.1 eV, the electron of H-atom is excited to $$3^{rd}$$ shell.
Thus, possible transactions are 3 i.e $$ 3\rightarrow2 , 2 \rightarrow 1 $$ and $$3\rightarrow 1$$

Chemistry

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image