The irreducible factor form of $49 a b$ is

7 a b

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7 \times a b

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7 \times 7 \times a \times b

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7 \times 7 \times a b

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Solution

The correct option is C $7 \times 7 \times a \times b$
$49 a b = 7 \times 7 \times a \times b$
$∴$ The irreducible factor form of $49 a b$ is $7 \times 7 \times a \times b$ .

So, option C is correct.

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What is the product of $(a + b)$ and $7 a^{2}$ $b^{2}$ ?

\begin{matrix} A & B & 7 \\ + & 7 & A & B \end{matrix} \bar{\begin{matrix} 9 & 8 & A \end{matrix}}

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