The IUPAC name of the following compound is?
4-Ethyl-2, 3, 4-trimethylheptane
Clearly the given compound is an alkane.There are no multiple bonds
primary suffix = ane
Now let us select the longest chain
The longest chain is (7 carbon atoms)
Also, the numbering could be done in the inverse direction to obtain the longest chain.
In the former numbering scheme, the number of substituents is 4. In the latter, the number of substituents is 4. We choose to number the chain in the direction that gives the lowest set of locants to the substituents.
So the former is preferable as the locants {2, 3, 4, 4} are lower than {4, 4, 5, 6} at the first point of difference.
Word root = hept
Secondary prefix = 4-Ethyl-2,3, 4-trimethyl
Hence the IUPAC name is
(c) 4-Ethyl-2,3,4-trimethylheptane