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Question

The key for opening a door is in a bunch of 10 keys. A man attempts to open the door by trying the keys at random discording the wrong key. The probability that the door is opened in the 5th trial is

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Solution

Given there are 10 keys in a bunch
i.e., there are 9 wrong keys and 1 correct key
probability that door is opend in 5th trial is
i.e., in 1st,2nd,3rd and 4st trial wrong key is
selected so, probability of selecting wrong key in 1st,2nd,3rd
and 4st trial is 910×89×78×67
and probability of selecting correct key in 5th
trial is 16
910×89×78×67×16=160

1044874_1174401_ans_6c0c4a624e9d4494bab8b0e518623764.png

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