The kinetic energy of a moving body is given by $K = 2 v^{2}$ , $K$ being in joules and $v$ in m/s. Its momentum when traveling with a velocity of $2 m s^{- 1}$ will be :

16 k g m s^{- 1}

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4 k g m s^{- 1}

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8 k g m s^{- 1}

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2 k g m s^{- 1}

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Solution

The correct option is A $8 k g m s^{- 1}$
$K = \frac{1}{2} m v^{2} = 2 v^{2}$
$\Rightarrow m = 4 k g$
$\to p = m . \to v$
$= 4 \times 2$
$= 8 k g m / s$

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The kinetic energy of a moving body is given by K=2v2, K being in joules and v in m/s. Its momentum when traveling with a velocity of 2 ms−1 will be :

The correct option is A 8 kgms−1K=12mv2=2v2⇒m=4kg→p=m.→v =4×2 =8 kgm/s

The kinetic energy of a moving body is given by $K = 2 v^{2}$ , $K$ being in joules and $v$ in m/s. Its momentum when traveling with a velocity of $2 m s^{- 1}$ will be :

The correct option is A $8 k g m s^{- 1}$
$K = \frac{1}{2} m v^{2} = 2 v^{2}$
$\Rightarrow m = 4 k g$
$\to p = m . \to v$
$= 4 \times 2$
$= 8 k g m / s$