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Question

The kinetic energy of a projectile at the highest point is half of the initial kinetic energy. What is the angle of projection with the horizontal?

A
30
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B
45
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C
60
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D
90
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Solution

The correct option is B 45
Let (KE)i and (KE)h be the initial kinetic energy and kinetic energy at highest point respectively.
Let v be the initial velocity of projectile.
At highest point, the velocity of projectile =vcosθ
According to question
(KE)h=12(KE)i
12mv2cos2θ=12(12mv2)
cos2θ=12
cosθ=12
θ=45

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