The kinetic energy of - - particle emitted in the - - decay of 88 Ra 226 is - given- mass number of Ra - 222 u -

The correct option is D 4.871 MeV [ _ 88 R a^ 226 → R_ n ^ 222 +2H_ e ^ 4; Q=[226.02540 222.01750 4.00260]× 931.5Mev; =0.0053× 931.5= ...

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Standard XII

Physics

Binding Energy

The kinetic e...

Question

The kinetic energy of $α$ - particle emitted in the $α$ - decay of $_{88} {R a}^{226}$ is [ given, mass number of Ra = 222 u ]

5.201 Me V

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3.301 Me V

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6.023 MeV

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4.871 MeV

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Solution

The correct option is D 4.871 MeV
$\begin{matrix} _{88} R a^{226} \to R_{n}^{222} + 2 H_{e}^{4} Q = [226.02540 - 222.01750 - 4.00260] \times 931.5 M e v = 0.0053 \times 931.5 = 4.94 M e v K . E = \frac{(A - 4) Q}{A} = \frac{226 - 4}{226} \times 4.94 = 4.85 M e v Q = 4.94 M e v, K . E = 4.85 M e v \end{matrix}$

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Similar questions

Q. The kinetic energy of

α - p a r t i c l e

emitted in the

α - d e c a y

_{88} R a^{226}

is [given, mass number of Ra=222 u]

Find the Q-value and the kinetic energy of the emitted

α

- Particle in the

α

-decay of (a)

_{86}^{220} R n

and (b)

_{88}^{226} R a

Given:

m (_{88}^{226} R a) = 226.02540 u

m (_{86}^{222} R n) = 222.01750 u

m (_{84}^{216} P o) = 216.00189 u

Suppose a $_{88}^{226} R a$ nucleus at rest and in ground state undergoes $α$ -decay to a $_{86}^{222} R n$ nucleus in its excited state. The kinetic energy of the emitted $α$ particle is found to be $4.44 M e V$ . $_{86}^{222} R n$ nucleus then goes to its ground state by $γ$ -decay. The energy of the emitted $γ$ photon is $k e V$ .

[Given : atomic mass of $_{88}^{226} R a = 226.005 u$ , atomic mass of $_{86}^{222} R n = 222.000 u$ , atomic mass of $α$ particle = $4.000 u, 1 u = 931 M e V / c^{2}, c$ is speed of light]

Q. A nucleus of mass 218 amu in free state decays to emit an

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The kinetic energy of α - particle emitted in the α - decay of 88Ra226 is [ given, mass number of Ra = 222 u ]

The correct option is D 4.871 MeV88Ra226→R222n+2H4eQ=[226.02540−222.01750−4.00260]×931.5Mev=0.0053×931.5=4.94MevK.E=(A−4)QA=226−4226×4.94=4.85MevQ=4.94Mev,K.E=4.85Mev

The kinetic energy of $α$ - particle emitted in the $α$ - decay of $_{88} {R a}^{226}$ is [ given, mass number of Ra = 222 u ]