The largest integer that divides product of any four consecutive integers is

4

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6

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12

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24

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Solution

The correct option is A $24$
Consider $1 \times 2 \times 3 \times 4 = 24$
$2 \times 3 \times 4 \times 5 = 120$
$3 \times 4 \times 5 \times 6 = 360$
All are divisible by $24$ which is the largest number given in options.

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