Question

# The latent heat of fusion of ice is $$330 J/g$$. Calculate the number of photons of radiation of frequency $$5 \times 10^{13} s^{-1}$$ to cause the melting of $$1 mole$$ of ice. Take $$h= 6.6 \times 10^{-34} J.sec^{-1}$$. Express your answer as $$x \times 10^{22}$$. What is the value of $$x$$?

Solution

## Energy required to melt 1 mole of ice $$=18\times 330 J$$Energy given by '$$n$$' photons$$=n\times hv$$$$\therefore n\times h\times s\times 10^{13}=18\times 330$$$$n=\cfrac{18\times330}{6.6\times 10^{-34}\times 5\times 10^{13}}$$$$=\cfrac{5440}{33\times 10^{-21}}=18\times 10^{22}$$$$\therefore x=18$$Chemistry

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