wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The least count of a screw gauge is 0.001 cm.The diameter of a wire measured by it is 0.225 cm . Find out the percentage error in this measurement.

A
0.05
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.001
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.44
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
0.11
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 0.44
The formula for calculating percentage error is least count of a
screw gauge divided by diameter of the wire, and then
multiplied by 100.
In this case, it would be, 0.001 divided by
0.225 and the result multiplied by 100.
And based on the calculation,
the answer is 0.44.
Hence, Option C is correct .

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Vernier Callipers and Screw Guage
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon