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Question

The least number which gives a remainder of 2, 3 and 4 when successively divided by 3,x and 8 respectively is 71. Find x.


  1. 4

  2. 6

  3. 5

  4. 7


Solution

The correct option is C

5



Solving, we get (4x + 3)×3+2 = 71 x=5.

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