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Question

The length and breadth of a conference hall are in the ratio 7 : 4 and its perimeter is 110 m. Find:

(i) Area of the floor of the hall.

(ii) number of tiles, each a rectangle of size 25cm×20cm, required for flooring of the hall.

(iii) The cost of the tiles at the rate of Rs 1,400 per hundred tiles.


Solution

Ratio in length and breadth =7 : 4

Perimeter =110 m

Length +Breadth =1102=55m

Sum of ratios =7+4=11

Length =55×711=35m and breadth =\frac{55 \times 4}{11}=20 m

(i)Area of floor =l×b =35×20=700m2

(ii)Size of tile =25 cm × 20 cm

=25×20100×100

=120m2

Number of tiles

=Area of floorArea of one tile

=700×201=14000

(iii)Cost of tiles =Rs 1400 per 100 tiles 

Toal cost =14000×1400100

=Rs 196000

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