The length and the midpoint of the chord 4x-3y+5=0 w.r.t circle $x^{2} + y^{2} - 2 x + 4 y - 20 = 0$ is

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Solution

The correct option is A

$2 \sqrt{r^{2} - d^{2}} = 8 M . P = (\frac{- 7}{5}, \frac{- 1}{5})$ , where r is the radius of the circle and d is the perpendicular distance of the line from the centre of the circle.

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Similar questions

x^{2} + y^{2} + 2 x + 3 y + 1 = 0

x^{2} + y^{2} + 4 x + 3 y + 2 = 0

4 x - 3 y + 5 = 0

x^{2} + y^{2} - 2 x + 4 y - 20 = 0

C = (7, 1)

A

x^{2} + y^{2} - 4 x - 4 y = 0

x^{2} + y^{2} = 16

P

x^{2} + 8 x + y^{2} + 12 x + 36 = 0

A P

4 x - 3 y - 10 = 0

x^{2} + y^{2} - 2 x + 4 y - 20 = 0

x^{2} + y^{2} + 2 x + 2 y + 1 = 0, x^{2} + y^{2} + 4 x + 3 y + 2 = 0

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