Question

# The length of a rectangle is twice of its breadth. If its perimeter is $$48\ cm$$, find the dimensions of the rectangle?

Solution

## Let, the dimensions of the rectangle be $$x \ cm, y \ cm$$ respectivelyGiven that, $$x = 2y$$and Perimeter $$= 48 \ cm$$i.e., $$2(x + y) = 48$$$$\implies 2(2y + y) = 48$$$$\implies 6y = 48$$$$\implies y = \dfrac{48}{6} = 8$$and $$x = 2y = 2\times 8 = 16$$$$\therefore$$ the dimensions of the rectangle are $$16 \ cm, 8 \ cm$$ respectivelyMathematics

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