Question

# The length of a seconds hand in watch is $$1$$ $$cm$$. The change in velocity of its tip in $$15\ s$$ is

A
zero
B
π302 cm/s
C
π30 cm/s
D
π230 cm/s

Solution

## The correct option is A $$\displaystyle \dfrac{\pi\sqrt{2} }{30}\ cm/s$$$$v=\omega r \\ v=1\times \dfrac{2 \pi}{60}\ cm/s = \dfrac{\pi}{30}\ cm/s$$The magnitude of velocity of tip of the seconds hand remains constant only its direction changes by $$360^0$$ in $$60\ secs$$, i.e., $$90^o$$ in $$15\ secs$$.Change in velocity  $$\Delta v=v\sqrt { 2 } =\dfrac { \pi \sqrt { 2 } }{ 30 }\ cm/s$$Physics

Suggest Corrections

0

Similar questions
View More

People also searched for
View More