The length of the wire shown in figure (15-E8) between the pulley is 1⋅5 m and its mass is 12⋅0 g. Find the frequency of vibration with which the wire vibrates in two loops leaving the middle point of the wire between the pulleys at rest.
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Length of the wire between two pulleys (L) = 1.5 m
Mass of the wire = 12 gm
Fundamental frequency is given by:
For second harmonic (when two loops are produced):