Question

The level of water in a tank is 5m high. A hole of area of cross section 1 cm${}^2$ is made at the bottom of the tank. The rate of leakage of water from the hole in $m^3{s}^{-1}$ is ( g $=$ 10ms${}^{-2}$):

• A. ${10}^{-3}$
• B. ${10}^{-4}$
• C. $10$
• D. ${10}^{-2}$

Answer 1

The correct option is A ${10}^{-3}$

Velocity of water from the hole= $\sqrt{2\times 5\times 10}=10m/s$
So, $Q=AV=1\times {10}^{-4}{m}^2\times 10m/s$
$={10}^{-3}{m}^3/s$