Question

# The level of water in a tank is 5m high. A hole of area of cross section 1 cm$$^{2}$$ is made at the bottom of the tank. The rate of leakage of water from the hole in $$m^{3}s^{-1}$$ is ( g $$=$$ 10ms$$^{-2}$$):

A
103
B
104
C
10
D
102

Solution

## The correct option is A $$10^{-3}$$Velocity of water from the hole= $$\sqrt{2 \times 5 \times 10}=10 m/s$$So, $$Q=AV=1 \times 10^{-4} m^{2} \times 10m/s$$$$= 10^{-3} m^{3}/s$$Physics

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