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Question

The light sensitive compound on most photographic films is silver bromide AgBr. A film is exposed when the light energy absorbed dissociates this molecule into its atoms. The energy of dissociation of AgBr is 105Jmol1. For a photon that is just able to dissociate a molecule of AgBr, the photon energy is

A
1.04 eV
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B
2.08 eV
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C
3.12 eV
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D
4.16 eV
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Solution

The correct option is A 1.04 eV
1 mole of AgBr contains 6.022×1023 molecules and 1J of energy is equivalent to 6.24×1018eV.
Thus, energy needed to dissociate 1 molecule of AgBr is given by:

E=105×6.24×10186.022×1023=1.04eV

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