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Question

The line 4x + 4y – 11 = 0 intersects the circle x2+y26x4y+4=0 at A and B. The point of intersection of the tangents at A, B is
  1. (–1, – 2)
  2. (1, 2)
  3. (–1, 2)
  4. (1, –2)


Solution

The correct option is A (–1, – 2)
The point of intersection of the tangents at A, B is the pole of 4x + 4y – 11 = 0 with respect to x2+y26x4y+4=0(x3)2+(y2)2=32
 Required point=(39(4)12+811,29(4)12+811)=(1,2)

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