The line joining points 1,1,2 and 3,-2,1 meets the plane 3x+2y+z=6 at the point
1,1,2
3,-2,1
2,-3,1
3,2,1
Calculate the point of contact.
The straight line joining the points 1,1,2&3,-2,1 is given as
x-12=y-1-3=z-2-1=r.
Then, the point is 2r+1,1-3r,2-r which lies on 3x+2y+z=6.
32r+1+21-3r+2-r=6r=1
So, the required point is
2×1+1,1-3×1,2-13,-2,1
Hence, option B is correct.