CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The line x2y1=0 intersects the circle x2+y2+4x2y5=0 at the points P and Q, then 5PQ is

Open in App
Solution

Given circle x2+y2+4x2y5=0
(x+2)2+(y1)2=10
Now r=10 and center C(2,1)
length of perpendicular from C on line x2y1=0 will be
d=|221|5=5
Hence PQ= length of the chord
PQ=2105=25 units

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Circle and Point on the Plane
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon