CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The line xcosα+ysinα=p touches the hyperbola
x2a2y2b2=1 if


A

a2cos2αb2sin2α=p2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
a2cos2αb2sin2α=p
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
a2cos2αb2cos2α=2p
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
a2cos2α+b2sin2α=p
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A

a2cos2αb2sin2α=p2


A given line y = mx + c touches hyperbola when,

c = a2m2 b2 . . . (1)

Given line is,y=xcotα+p cosec α ...(2)
(1) and (2) gives

p cosec α = a2 cot2α b2

p2 cosec2 α = a2 cos2αsin2αb2

p2=a2cos2αb2sin2α


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Basic Concepts
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon