The liquids shown in figure in the two arms are mercury (specific gravity = 13.6) and water. if the difference of heights of the mercury columns is 2 cm, find the height h of the water column.

0.27 cm

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27 cm

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2 mm

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27 dm

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Solution

The correct option is B
27 cm

Suppose the atmospheric pressure = $P_{0}$

Pressure at A = $P_{0} + h (1000 k g m^{- 3}) g$

Pressure at B = $P_{0} + (0.02 m) (13600 k g m^{- 3}) g$

These pressures are equal as A and B are at the same horizontal level. Thus,
$h = (0.02 m) 13.6$

$= 0.27 m = 27 c m$

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The liquids shown in the figure in the two arms are mercury (specific gravity = 13.6) and water. if the difference of heights of the mercury columns is 2 cm, find the height h of the water column. Acceleration due to gravity $g = 10 m / s^{2}$

The liquid shown in figure in two arm are mercury (specific gravity = 13.6) and water if the difference of height of the mercury column is 2 cm find the height h of the water column.

Q. The liquids shown in figure in the two arms are mercury (specific gravity

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) and water. If the heights of the mercury column and water column is as shown, find the height

h

of the water column.

Q. The liquids shown in fig. in the two arms are mercury (specific gravity

= 13.6

) and water. If the difference of heights of the mercury columns is

2 c m

, find the height h of the water column.

The liquids shown in figure in the two arms are mercury (specific gravity = 13.6) and water. if the difference of heights of the mercury columns is 2 cm, find the height h of the water column.

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The liquids shown in figure in the two arms are mercury (specific gravity = 13.6) and water. if the difference of heights of the mercury columns is 2 cm, find the height h of the water column.

The correct option is B 27 cm Suppose the atmospheric pressure = P0 Pressure at A = P0+h(1000 kg m−3) g Pressure at B = P0+(0.02 m)(13600 kg m−3) g These pressures are equal as A and B are at the same horizontal level. Thus, h=(0.02 m)13.6 =0.27 m=27 cm