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Question

The loop is shown moves with a velocity v in a uniform magnetic field of magnitude B, directed into the paper. The potential difference between P and Q is e. Then:


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A
e=12Blv
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B
e=Blv
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C
P is negative with respect to Q
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D
Q is negative with respect to P
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Solution

The correct option is A e=12Blv
Given: potential difference =e, velocity=v, B=into the the plane of plane of paper.
Solution: As we know the formula of the formula of motional emf
ε=Bvl
But here l=l2
So,ε=Bvl2
Hence the correct answer is A

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