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Question

The lower end of a capillary tube is immersed in mercury. The level of mercury in the tube is found to be 2 cm below the outer level. If the same tube is immersed in water, up to what height will the water rise in the capillary?


Solution

hHg=2THg cos θHgrρHg g

hw=2Tw cos θwrρw g

Where, the symbols have their usual meanings. 

hwhHg=hwhHg×ρHgρw×cos θcos θHg

=(0.0750.465)×(13.6)×(cos 0cos 40)

= 2.9

hw=2×(2.9)=5.8cm 

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