The magnetic induction at center $O$ (figure) is

\frac{μ_{0} I}{2 a} + \frac{μ_{0} I}{2 b} ⨂

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\frac{{3 μ}_{0} I}{8 a} + \frac{μ_{0} I}{8 b} ⨂

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\frac{{3 μ}_{0} I}{8 a} - \frac{μ_{0} I}{8 b} ⨂

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\frac{{3 μ}_{0} I}{8 a} + \frac{μ_{0} I}{8 b} ⨀

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Solution

The correct option is B $\frac{{3 μ}_{0} I}{8 a} + \frac{μ_{0} I}{8 b} ⨂$
$B = \frac{3}{4} [\frac{μ_{0} I}{2 a}] + \frac{1}{4} [\frac{μ_{0} I}{2 b}]$

$B = \frac{3 μ_{0} I}{8 a} + \frac{μ_{0} I}{8 b}$

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The magnetic induction at center O (figure) is

The correct option is B 3μ0I8a+μ0I8b⨂B=34[μ0I2a]+14[μ0I2b]B=3μ0I8a+μ0I8b

The magnetic induction at center $O$ (figure) is

The correct option is B $\frac{{3 μ}_{0} I}{8 a} + \frac{μ_{0} I}{8 b} ⨂$
$B = \frac{3}{4} [\frac{μ_{0} I}{2 a}] + \frac{1}{4} [\frac{μ_{0} I}{2 b}]$

$B = \frac{3 μ_{0} I}{8 a} + \frac{μ_{0} I}{8 b}$