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Question

The magnetic moments of complexes given below are in the order:


(I) [Ni(CO)4] (II) [Mn(CN)6]4 (III) [Cr(NH3)6]3+ (IV) [CoF6]3.

A
(I)>(II)>(III)>(IV)
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B
(I)<(II)<(III)<(IV)
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C
(II)>(III)>(IV)>(I)
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D
(IV)<(II)<(I)<(III)
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Solution

The correct option is B (I)<(II)<(III)<(IV)
As magnetic moment μ=n(n+2) , where n is no. of unpaired electron.

In [Ni(CO)4],d8 configuration, low spin complex, 0 unpaired electron.

In [Mn(CN)6]4,d5 configuration, low spin complex, 1 unpaired electron.
In [Cr(NH3)6]3+,d3 configuration, 3 unpaired electron.

In [CoF6]3,d6 configuration, high spin complex, 4 unpaired electron.

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