The magnetizing field of $1600 A m^{- 1}$ produced a magnetic flux of $2.4 \times 10^{- 5} W b$ in a bar iron of cross section $0.2 {c m}^{2}$ . Determine the relative permeability, intensity of magnetization and susceptibility of the bar magnet.

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Solution

$B = μ H B = 1600 μ$
Manetic field $= \frac{f l u x}{A r e a}$
$B = \frac{2.4 \times 10^{- 5}}{0.2 \times \times 10^{- 4}} B = 120 T μ = \frac{120}{1600} = \frac{3}{40}$

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The magnetizing field of 1600 Am−1 produced a magnetic flux of 2.4×10−5 Wb in a bar iron of cross section 0.2cm2. Determine the relative permeability, intensity of magnetization and susceptibility of the bar magnet.

B=μHB=1600μManetic field =fluxAreaB=2.4×10−50.2××10−4B=120Tμ=1201600=340

The magnetizing field of $1600 A m^{- 1}$ produced a magnetic flux of $2.4 \times 10^{- 5} W b$ in a bar iron of cross section $0.2 {c m}^{2}$ . Determine the relative permeability, intensity of magnetization and susceptibility of the bar magnet.

$B = μ H B = 1600 μ$
Manetic field $= \frac{f l u x}{A r e a}$
$B = \frac{2.4 \times 10^{- 5}}{0.2 \times \times 10^{- 4}} B = 120 T μ = \frac{120}{1600} = \frac{3}{40}$