The magnification of an object placed in front of a convex lens is +2. The focal length of the lens is 2.0 metres. Find the distance by which object has to be moved to obtain a magnification of −2 (in cm).
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Solution
For magnification +2,u=−x,v=−2x and f=2.0m From 1v−1u=1f, we have 1−2x+1x=1z x=1.0m For magnification of −2,u=−y,v=+2y,f=2.0m we have 12y+1y=12⇒y=3.0cm.