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Question

The magnifying power of an astronomical telescope is 0.5. The power of its eyepiece is 10 D. What is the power of its objective

A
+1 D
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B
+ 20D
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C
2 D
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D
+ 4 D
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Solution

The correct option is D + 20D
The magnifying power of an astronomical
telescope =f0fe=PeP0(:.P0=1f0)
where f0= focal length of objective.
P0= power of objective
Pc= Power of eye lens.
fe= focal length of eye lens.
given
magnifying power =0.5
Pe=100.5=+10P0P0=+20D
So option B is correct

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