Question

The main scale of a vernier callipers reads in millimetre and its vernier is divided into $10$ divisions which coincides with $9$ divisions of the main scale. The reading for shown situation is found to be $\frac{12x}{10}mm$. Find the value of $x$.

Answer 1

Least count $=\frac{1mm}{10}=0.1mm$
zero error $=-(10-6)\times 0.1=-0.4mm$
Reading $=MSR+LC\times VSR\pm$ Error
Reading $=6+8$$\times \left(0.1\right)-(-0.4)=7.2mm$
Comparing it with $\frac{12x}{10}$,
We get the value of $x=6$
Final answer:$6$