Question

# The major product of the following reaction is:$$CH_3\underset{Br}{\underset{|}{C}}HCH_2\underset{Br}{\underset{|}{C}}HCH_2CH_3\xrightarrow[heat]{KOH, CH_3OH}$$

A
CH3CH=CHCH=CHCH3
B
CH3CH=C=CHCH2CH3
C
CH2=CHCH2CH=CHCH3
D
CH2=CHCH=CHCH2CH3

Solution

## The correct option is A $$CH_3CH=CH-CH=CHCH_3$$Conjugated alkene in which double bonds are more substituted is the major product. When dibromoalkane is heated with $$\displaystyle CH_3OH/KOH$$, it undergoes dehydrohalogentation. Two molecules of $$\displaystyle HBr$$ are eliminated to form alkadiene.ChemistryNCERTStandard XII

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