The major product of the given substitution reaction is
$(C H_{3})_{2} C = C H - C H_{2} - B r H_{2} O - - \to$

(C H_{3})_{2} (B r) C - C H = C H_{2}

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(C H_{3})_{2} C = C H - C H_{2} - O H

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(C H_{3})_{2} (O H) C - C H = C H_{2}

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None of the above

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Solution

The correct option is B $(C H_{3})_{2} C = C H - C H_{2} - O H$
Weak electrophile $H_{2} O$ is used in the given substitution reaction hence, it will favour $S_{N} 1$ mechanism.
Allyl system favour both $S_{N} 1$ and $S_{N} 2$ mechanism but due to formation of a stable carbocation, they undergo
$S_{N} 1$ reaction at a faster rate.

Major and minor products are determined by steric hindrance.
The attack of nucleophile is faster at the less-hindered end of the allylic system.
Major product also depends on the stability of the alkene compound formed.
Since, (c) is the more substituted alkene and has a less steric carbocation intermediate.
It is the major product.

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$C H \equiv C H + H_{2} \to C H_{2} = C H_{2}$

The given reaction is an example of substitution reaction.

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