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Question

The marks obtained by 100 students of a class in an examination are given below:

MarksNumber of students052510510156152082025102530253035203540184045445502

Draw cumulative frequency curves by using (i) 'less than's series and (ii) 'more than' series.

Hence,find the median.

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Solution

(i) From the given table, we may prepare the less than frequency table as shown below:

Marks No. of students
Less than 5 2
Less than 10 7
Less than 15 13
Less than 20 21
Less than 25 31
Less than 30 56
Less than 35 76
Less than 40 94
Less than 45 98
Less than 50 100

We plot the points A(5,2), B(10,7), C(15,13), D(20,21), E(25,31), F(30,56), G(35,76), H(40,94), I(45,98), and J(50,100).

Join AB,BC,CD,DE,EF,FG,GH,HI,IJ and JA with a free hand to get the curve representing the less than types series.

(ii) More than series:

Marks No. of students
More than 0 100
More than 5 98
More than 10 93
More than 15 87
More than 20 79
More than 25 69
More than 30 44
More than 35 24
More than 40 6
More than 45 2

Now on the same graph paper, we plot the points (0,100), (5,98), (10,94), (15,76), (20,56), (25,31), (30,21), (35,13), (40,6) and (45,2).

Join, with a free hand to get the more than type series.

Scale: Along x-axis: 1 big division = 5 marks

Along y-axis: 2 big division = 10 student

The two curves intersect at point L. Draw LM⊥OX cutting the x-axis at M. Clearly, M= 29.5.

Hence, Median = 29.5


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