The mass (in g) of 10 millimoles of $F e S O_{4}$ is:

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Solution

The molar mass of $F e S O_{4} = 56 + 32 + 16 \times 4 = 152$ g/mol

Mass of 1 mole of $F e S O_{4} = 152$ g

Mass of 10 millimoles $F e S O_{4} = 152 \times 10^{- 2} g$
$= 1.52 g$

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